Show work and explain.
Nodal analysis-2 Solve the following circuit using nodal analysis. Answer: VA = 175V, VB = 420V, VC = 1155V. VD = 0V. Nodal analysis-3 Repeat the previous problem. except choose node B as reference (ground) [ Answer: Same as the previous except subtract 420 volts from all the values; Nodal analysis-4 Repeat the previous problem, except choose node C as reference (ground)
Solution
Here applying NODAL VOLTAGE ANALYSIS to the given circuit we have ,
(Va-Vc)/7+(Va-Vb)/7+Va=0...................(1)
for node 2:- we have
Vc-Va/7+Vc-Vb/7= 245A....................(2).
For node (3) we have
Vb/6+Vb-vA/7+Vb-Vc/7=0.........................(3).
Simplifying these three equations we can have
9Va-Vb-Vc=0;................(a)
-Va-Vb+2Vc=1715.........(b)
-6Va+19Vb-6Vc=0......(c).
sOLVING THESE equations we have Va=175V,Vb=420V,Vc=1155V.
rEPEAT THE SAME PROCEDURE WITH b GROUNDED.
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Show work and explain- Nodal analysis-2 Solve the following circuit us.docx
1. Show work and explain.
Nodal analysis-2 Solve the following circuit using nodal analysis. Answer: VA = 175V, VB =
420V, VC = 1155V. VD = 0V. Nodal analysis-3 Repeat the previous problem. except choose
node B as reference (ground) [ Answer: Same as the previous except subtract 420 volts from all
the values; Nodal analysis-4 Repeat the previous problem, except choose node C as reference
(ground)
Solution
Here applying NODAL VOLTAGE ANALYSIS to the given circuit we have ,
(Va-Vc)/7+(Va-Vb)/7+Va=0...................(1)
for node 2:- we have
Vc-Va/7+Vc-Vb/7= 245A....................(2).
For node (3) we have
Vb/6+Vb-vA/7+Vb-Vc/7=0.........................(3).
Simplifying these three equations we can have
9Va-Vb-Vc=0;................(a)
-Va-Vb+2Vc=1715.........(b)
-6Va+19Vb-6Vc=0......(c).
sOLVING THESE equations we have Va=175V,Vb=420V,Vc=1155V.
rEPEAT THE SAME PROCEDURE WITH b GROUNDED.
